/6 subnet: mask 252.0.0.0, 67,108,864 addresses

Everything about a /6 network, with the CIDR calculator pre-filled — change the IP to calculate your own block.

Enter a CIDR range above to calculate

Is an IP inside a CIDR block?

Yes — 10.0.42.7 is inside 10.0.0.0/16.

Do two CIDR blocks overlap?

Overlap — 10.0.128.0/20 sits inside 10.0.0.0/16 (10.0.128.0 – 10.0.143.255).

CIDR blocks never partly overlap: one is inside the other, or they don't touch at all. Overlapping VPCs can't be peered.

/6 at a glance

Subnet mask
252.0.0.0
Wildcard mask
3.255.255.255
Mask in binary
11111100.00000000.00000000.00000000
Host bits
26
Total addresses
67,108,864
Usable hosts
67,108,862 (network and broadcast address excluded)
Equivalent /24 networks
262,144

Splitting a /6 into smaller subnets

  • 2 × /7 — 33,554,432 addresses each (33,554,430 usable)
  • 4 × /8 — 16,777,216 addresses each (16,777,214 usable)
  • 8 × /9 — 8,388,608 addresses each (8,388,606 usable)
  • 16 × /10 — 4,194,304 addresses each (4,194,302 usable)

Frequently asked

What is the subnet mask for /6?

252.0.0.0. The first 6 bits are network bits and the remaining 26 are host bits; the wildcard (inverse) mask is 3.255.255.255.

How many IP addresses are in a /6?

67,108,864 in total. 67,108,862 of them can be assigned to hosts, because the first is the network address and the last is the broadcast address.

CIDR to subnet mask cheat sheet

CIDRSubnet maskAddressesUsable hosts
/8255.0.0.016,777,21616,777,214
/12255.240.0.01,048,5761,048,574
/16255.255.0.065,53665,534
/17255.255.128.032,76832,766
/18255.255.192.016,38416,382
/19255.255.224.08,1928,190
/20255.255.240.04,0964,094
/21255.255.248.02,0482,046
/22255.255.252.01,0241,022
/23255.255.254.0512510
/24255.255.255.0256254
/25255.255.255.128128126
/26255.255.255.1926462
/27255.255.255.2243230
/28255.255.255.2401614
/29255.255.255.24886
/30255.255.255.25242
/31255.255.255.25422
/32255.255.255.25511
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